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Chapter 11: Q. 10 (page 772)

If a graph of a system of linear inequalities cannot be contained in any circle, then it is said to be ___ .

Short Answer

Expert verified

On completing the statement, we get,

"If a graph of a system of linear inequalities cannot be contained in any circle, then it is said to beunbounded."

Step by step solution

01

Step 1. Given information.

Consider the given statement,

"If a graph of a system of linear inequalities cannot be contained in any circle, then it is said to be ___."

On completing the statement,

"If a graph of a system of linear inequalities cannot be contained in any circle, then it is said to be unbounded."

02

Step 2. Explanation for completing the statement.

Consider the given question,

A graph is unbounded if the graph of a system of linear inequalities cannot be contained in any circle.

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Most popular questions from this chapter

Graph the equation:y+4=x2

In Problems 5鈥�24, graph each equation of the system. Then solve the system to find the points of intersection.

y=x;y=2-x

Solve each system of equations. If the system has no solution, say that it is inconsistent.

4x+5y=-3-2y=-8

In Problems, use the division algorithm to rewrite each improper fraction as the sum of a quotient and proper fraction. Find the partial fraction decomposition of the proper fraction. Finally, express the improper fraction as the sum of a quotient and the partial fraction decomposition.

x5+x4-x2+2x4-2x2+1

Solve the equation:

3x+4=8-x
See all solutions

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