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use the Binomial Theorem to find the indicated coefficient or term.

The fifth term in the expansion of (x + 3)7

Short Answer

Expert verified

The fifth term is 2835 x3

Step by step solution

01

. Given information 

In this question (x+3)7 is given

We have to find out the fifth term

02

. Expansion of  (x+3)7 using The Binomial Theorem 

According to the binomial theorem

Letxandaberealnumbers.Foranypositiveintegern,wehave(x+a)n=n0xn+n1axn-1+n2a2xn-2+.......+njajxn-j+.....+nnan

based on this theorem, the expanded form of (x+3)7 is

localid="1647340067248" (x+3)7=70x7+71×31×x7-1+72×32×x7-2+73×33×x7-3+74×34x7-4......+76×36×(2x)9-8+77×37=70x7+713x6+929x5+9327x6+7481x3......+76729x+772187

03

Step 3. Description of finding the fifth term

the fifth term from the expanded form is

7481x3=7!3!4!×81×x3=7×6×5×4!3×2×1×4!×81×x3=2835x3

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