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use the Binomial Theorem to find the indicated coefficient or term.

The coefficient of x3in the expansion of (2x+1)12

Short Answer

Expert verified

The coefficient x3is1760

Step by step solution

01

. Given information

here (2x+1)12 is given

we need to find the coefficient of x3

02

 step 2 . Expansion of  (2x+1)12 using The Binomial Theorem

According to the binomial theorem

Letxandaberealnumbers.Foranypositiveintegern,wehave(x+a)n=n0xn+n1axn-1+n2a2xn-2+.......+njajxn-j+.....+nnan

Then the expansion of (2x+1)12becomes

(2x+1)12=120(2x)12+121(1)(2x)12-1+...........+129(1)9(2x)12-9+1210(1)10(2x)12-10+1211(1)11(2x)12-11+1212112=120(2x)12+121(2x)11+.......+129(2x)3+1210(2x)2+1211(2x)1+1212

03

 Step 3. Description of finding the coefficient of x3

According to the question, the coefficient of x3 from the expanded term is

129(2)3(1)9,whichisequalto12!3!9!×23×1=12×11×10×9!3×2×1×9!×8=1760,thisiscoe.ofx3

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