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Precalculus Enhanced with Graphing Utilities

Sullivan

$Math Studyset 91影视 Explanations$ Math

6th Edition 路 1200 pages

ISBN: 9780321795465

Chapter 12: Q 28. (page 808)

In Problems 17鈥�28, write down the first five terms of each sequence.
$\{c_{n}\} = \{\frac{n^{2}}{2^{n}}\}$

Short Answer

Expert verified

The first five terms of the given sequence are $\frac{1}{2}, 1, \frac{9}{8}, 1, \frac{25}{32}$

Step by step solution

01

Step 1. Write the given sequence.

The given sequence is $\{c_{n}\} = \{\frac{n^{2}}{2^{n}}\}$

02

Step 2. Find the five terms.

To find the five terms in the sequence we substitute $1, 2, 3, 4 a n d 5 i n t o n$

$\{c_{1}\} = \frac{1^{2}}{2^{1}} = \frac{1}{2} \{c_{2}\} = \frac{2^{2}}{2^{2}} = 1 \{c_{3}\} = \frac{3^{2}}{2^{3}} = \frac{9}{8} \{c_{4}\} = \frac{4^{2}}{2^{4}} = 1 \{c_{5}\} = \frac{5^{2}}{2^{5}} = \frac{25}{32}$

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Most popular questions from this chapter

In Problems 29鈥�36, the given pattern continues. Write down the nth term of a sequence $\{a_{n}\}$ suggested by the pattern.

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$1, \frac{1}{2}, \frac{1}{4}, \frac{1}{8}, . . .$

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