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91Ó°ÊÓ

Solve the equation2sin2x-sinx-3=0,0≤x<2π

Short Answer

Expert verified

The solution of the equation is2Ï€3.

Step by step solution

01

Step 1. Given Information

Given trigonometric equation is 2sin2x-sinx-3=0,0≤x<2π.

Letsinx=y,then2y2-y-3=0

02

Step 2. Solving Equation

2y2-y-3=02y2-3y+2y-3=0y2y-3+12y-3=0y+12y-3=0y=-1,32

03

Step 3. Finding solution for sinx

We get sinx=-1,sinx=32,

role="math" localid="1646989043028" x=Ï€+Ï€2,2Ï€-Ï€2x=3Ï€2,

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