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In Problems 23–30, use the given zero to find the remaining zeros of each function.

gx=2x5-3x4-5x3-15x2-207x+108;zero:3i

Short Answer

Expert verified

The remaining answer is±3i,-12,3,4.

Step by step solution

01

Step 1. Given Information.

The given polynomial is

g(x)=2x5-3x4-5x3-15x2-207x+108

02

Step 2. Performing Long Division.

Here we apply the conjugate the Pairs Theorem. The degree of the polynomial is 5.

3i is zero of polynomial then it's conjugate -3i also zero of the polynomial. Now we have two zeros.

Since all the coefficients are g(x)are real and 3iis a root of gxthen -3iis also a root of gx. Then x+3ix-3iare factors of gx. So by divides x-3ix+3i=x2+9to gx.

(2x5-3x4-5x3-15x2-207x+108)(x2+9)=2x3-3x2-23x+12

03

Step 3. Factors of the finding polynomial.

Now, find the factors and apply the zero methods.

2x3-3x2-23x+12=2x2(x-4)-5x(x-4)-3(x-4)

And,

(x-4)(2x2-5x-3)=(x-4)(2x2-6x+x-3)=(x-4){2x(x-3)+1(x-3)}=(x-4)(2x+1)(x-3)

The zeros are±3i,-12,3,4.

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