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Graph each of the following functions:

y=x2-1x-1y=x3-1x-1y=x4-1x-1y=x5-1x-1

Is x=1a vertical asymptote? Why not? What is happening for x=1? What do you conjecture about y=xn-1x-1;n≥1an integer, for x=1?

Short Answer

Expert verified

The function is undefined at x=1, so there is no vertical asymptote there. There is a hole atx=1.

Step by step solution

01

Step 1. x=1 is not a vertical asymptote.

For all the function we are given here x=1is not a vertical asymptote. For vertical asymptote we put denominator equal to zero.

We see in every function it seems that vertical asymptote will be x=1but this is not so. Let us draw the graph of all these and then make conclusions. Also, as we write the function, we observe that in each has a common factor in numerator and denominator.

From this we come to the conclusion that x=1is not a vertical asymptote rather it is a hole.

02

Step 2. The graph of y=x2-1x-1 is

03

Step 3. The graph of y=x3-1x-1 is

04

Step 4. The graph of y=x4-1x-1 is

05

Step 5. The graph of y=x5-1x-1 is

06

Step 6. Explanation for x=1.

For x=1the function is undefined, so there is no vertical asymptote there.

Now for the function

y=xn-1x-1;n∈I∶Än≥1

Here also numerator and denominator have a common factor.

This means x=1is a hole.

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