/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 56 Solve each inequality algebraica... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each inequality algebraically.

(x-3)(x+2)<x2+3x+5

Short Answer

Expert verified

Solution set and the interval is:

{x|x>-114}(-114,∞)

Step by step solution

01

Step 1. Change the inequality to equal to zero. 

Change the inequality equal to zero to make it easier and then get the value of x

First arrange the inequality,

(x−3)(x+2)<x2+3x+5x2−x−6<x2+3x+5x2−x−6−x2−3x−5<0−4x−11<0

Make it equal to zero,

-4x-11=04x+11=0x=-114

02

Step 2. Form the intervals

From the obtained values of x, we can form the interval,

So the interval we have is:

(-∞,-114)∪(-114,∞)

03

Step 3. Form the table

Since, f(x)<0, so is negative.

check a number in each interval and evaluate the function to see whether it is satisfying the function.

IntervalNumber chosenResultant
(-∞,-114)
-31<0
(-114,∞)
5-31<0
04

Step 4. Solution set and interval

Since, only -31<0satisfy f. Thus,

role="math" localid="1646211136842" {x|x>-114}(-114,∞)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.