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91Ó°ÊÓ

Solve each inequality algebraically.

x+1x-3≤2

Short Answer

Expert verified

Solution set and the interval is:
{x|x<3orx≥7}(-∞,3)∪[7,∞)

Step by step solution

01

Step 1. Change the inequality to equal to zero. 

Change the inequality equal to zero to make it easier and then get the value of x

Arrange the inequality first,

x+1x-3≤2x+1x-3-2≤0x+1x-3-2·x-3x-3≤0x+1x-3-2x-6x-3≤0x+1-2x+6x-3≤0-x+7x-3≤0

Make it equal to zero,

-x+7x-3=0-x+7=0;x-3=0x=7;x=3

02

Step 2. Form the intervals

From the obtained values of x, we can form the interval,

So the interval we have is:

(-∞,3)∪(3,7)∪(7,∞)

03

Step 3. Form the table

Since, f(x)<0, so is negative.

check a number in each interval and evaluate the function to see whether it is satisfying the function.

IntervalNumber chosenResultant
(-∞,3)
1-3≤0
(3,7)
43≤0
(7,∞)
8-15≤0
04

Step 4. Solution set and interval

Since,

-3≤0,-15≤0satisfy f. Thus,

{x|x<3orx≥7}(-∞,3)∪[7,∞)

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