/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 40 Solve each inequality algebraica... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each inequality algebraically.

x+2x-4≥1

Short Answer

Expert verified

Solution to the inequality x+2x-4≥1isrole="math" localid="1646128818261" (4,∞).

Step by step solution

01

Step 1. Given information 

We have been given an inequality x+2x-4≥1.

We have to solve this inequality algebraically.

02

Step 2. Write the inequality so that a polynomial or rational expression f is on the left side and zero is on the right side 

x+2x-4≥1x+2x-4-1≥1-1(Subtract1frombothsides)x+2-1(x-4)x-4≥0(TakeLCD)x+2-x+4x-4≥06x-4≥0

03

Step 3. Determine the real numbers at which the expression f equals zero and at which the expression f is undefined.  

Assume f(x)=6x-4.

x-4=0x=4

04

Step 4. Form the intervals 

Using the values of x found in previous step, we can divide the real numbers in the intervals:

(-∞,4)∪(4,∞)

05

Step 5. Select a number in each interval and evaluate f at the number  

Create the following table:

Interval(-∞,4)
(4,∞)
Number chosen
05
Value of ff(0)=-32
f(5)=6
Conclusionnegativepositive
06

Step 6. Identify the interval

Since we want to know where f is positive or zero, we conclude that f(x)≥0in the intervalrole="math" localid="1646129255698" (4,∞).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.