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Precalculus Enhanced with Graphing Utilities

Sullivan

$Math Studyset 91影视 Explanations$ Math

6th Edition 路 1200 pages

ISBN: 9780321795465

Chapter 4: Q. 4 (page 241)

True or False : The graph of $f (x) = \frac{x}{x - 3}$ is above the x-axis for $x < 0$ or $x > 3$ , so the solution set of the inequality $\frac{x}{x - 3} 鈮� 0$ is ${x : x 鈮� 0 o r x 鈮� 3}$ ..

Short Answer

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Step by step solution

Step 1. The graph of f(x)=xx-3 is as follows.

The graph is above x-axis for $x < 0$ and $x > 3$ .

Step 2. The solution set of xx-3≥0 is {x:x≤0 or x≥3} is shown as :

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True or False : The graph off(x)=xx-3 is above the x-axis for x<0or x>3, so the solution set of the inequality xx-3鈮�0is {x:x鈮�0orx鈮�3}..

Short Answer

Step by step solution

Step 1. The graph of f(x)=xx-3 is as follows.

Step 2. The solution set of xx-3≥0 is {x:x≤0 or x≥3} is shown as :

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True or False : The graph of $f (x) = \frac{x}{x - 3}$ is above the x-axis for $x < 0$ or $x > 3$ , so the solution set of the inequality $\frac{x}{x - 3} 鈮� 0$ is ${x : x 鈮� 0 o r x 鈮� 3}$ ..