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Chapter 4: Q. 4 (page 209)

Find the zeros off(x)=x2+x-3.

Short Answer

Expert verified

The solution is-1-132,-1+132.

Step by step solution

01

Step 1. Given information.

The given function is,

f(x)=x2+x-3.

02

Step 2. Finding the nature of the roots.

On comparing the given function with the general form ax2+bx+cwe get,

a=1,b=1,c=-3

Now the discriminant will be

b2-4ac=1-41-3=1+12=13

Which is greater than zero then it will have two roots.

03

Step 3. Finding the zero.

Using the quadratic formula we will get the zeroes

x=-b卤b2-4ac2a=-1卤132

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Most popular questions from this chapter

One solution of the equation x3-8x2+16x-3=0 is 3.

Find the sum of the remaining solutions.

Find a rational function that might have the given graph.

Analyze each polynomial function using Steps 1through 8:

f(x)=x4-x3-6x2+4x+8.

Graph each rational function using transformations.

R(x)=x-4x

Find the real zeros of f. Use the real zeros to factor f. f(x)=2x3-5x2-4x+12
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