/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 39. In Problems 31– 40, find the c... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Problems 31– 40, find the complex zeros of each polynomial function. Write f in factored form.

f(x)=3x4-x3-9x2+159x-52

Short Answer

Expert verified

f(x)=(x+1)(3x-1)(x-2+3i)(x-2-3i)

Complex zeros are2±3i.

Step by step solution

01

Step 1. Given Information

The given polynomial isf(x)=3x4-x3-9x2+159x-52

Since a0=-52and an=3.

The factors of -52are±1,±2,±3,±4,±13,±26,±52and factors of 3are ±1,±3

Therefore, potential roots of fxare±1,±13,±2,±23,±4,±43,±13,±133,±26,±263,±52,±523

02

Step 2. Check for zeros

First, we will use synthetic division to determine the zero of fx,let us check at 13. We see that

. f13=0That is 13is a zero of polynomial.

fx=x-133x3-9x+156

03

Step 3. Factor 3x3-9x+156

3x3-9x+156=03x+4x2-4x+13=0

where x2-4x+13is not factorable.

04

Step 4. Factor x2-4x+13 by quadratic formula

x=4±16-522=4±-362x=4±6i2x=2±3i

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.