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use the given zero to find the remaining zeros of each function.

f(x)=2x4+5x3+5x2+20x-12;zero:-2i

Short Answer

Expert verified

The roots of the polynomial is2i,-2i,-3,12

Step by step solution

01

Given information

We are given a polynomialf(x)=2x4+5x3+5x2+20x-12

02

Find the zeros by synthetic divsion

We have,

f(x)=2x4+5x3+5x2+20x-12and 2i as one of the root

2i25520-124i10i-8-20-6i1225+4i10i-3-6i0

as 2i is one root then -2i is the second root

-2i25+4i10i-3-6i-4i-10i6i25-30

Now we have,

f(x)=(x-2i)(x+2i)(2x2+5x-3)

Now we factor the remaining term

2x2+5x-3=0(2x-1)(x+3)=0∴x=12orx=-3


03

Conclusion

The roots of the polynomial is2i,-2i,-3,12

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