Q. 22 Solve the inequality algebraical... [FREE SOLUTION]

91影视

Precalculus Enhanced with Graphing Utilities

Sullivan

$Math Studyset 91影视 Explanations$ Math

6th Edition 路 1200 pages

ISBN: 9780321795465

Chapter 4: Q. 22 (page 241)

Solve the inequality algebraically
$x^{3} + 8 x^{2} < 0$

Short Answer

Expert verified

Required solution set is $(- 鈭�, - 8)$ .

Step by step solution

Step 1. Given information

We are given an inequality,

$x^{3} + 8 x^{2} < 0$

Step 2.Finding the zeros

The zeros are given by,

$x^{3} + 8 x^{2} = 0 x^{2} (x + 8) = 0 x = 0 x + 8 = 0 x = - 8$

So, the intervals will be,

$(- 鈭�, - 8), (- 8, 0) and (0, 鈭�)$

Step 4. Selecting a test number in each interval

The table is as follows,

Interval	$(- 鈭�, - 8)$	$(- 8, 0)$	$(0, 鈭�)$
Chosen Number	$- 10$	$- 1$	$1$
Value of Function	localid="1646303382470" $f (- 10) = - 200$	$f (- 1) = 7$	$f (1) = 9$
Check	Negative	Positive	Positive

Hence the solution set is $(- 鈭�, - 8)$ .

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91影视

Solve the inequality algebraically
$x^{3} + 8 x^{2} < 0$

Short Answer

Step by step solution

Step 1. Given information

Step 2.Finding the zeros

Step 4. Selecting a test number in each interval

One App. One Place for Learning.

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91影视

Solve the inequality algebraicallyx3+8x2<0

Short Answer

Step by step solution

Step 1. Given information

Step 2.Finding the zeros

Step 4. Selecting a test number in each interval

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Pure Maths

Mechanics Maths

Decision Maths

Theoretical and Mathematical Physics

Logic and Functions

Applied Mathematics

Study anywhere. Anytime. Across all devices.

Solve the inequality algebraically
$x^{3} + 8 x^{2} < 0$