/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 103 is23a zero of f(x)=x7+6x5-x4+x+2... [FREE SOLUTION] | 91影视

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Precalculus Enhanced with Graphing Utilities

Sullivan

$Math Studyset 91影视 Explanations$ Math

6th Edition 路 1200 pages

ISBN: 9780321795465

Chapter 4: Q. 103 (page 211)

is $\frac{2}{3}$ a zero of $f (x) = x^{7} + 6 x^{5} - x^{4} + x + 2$ ? Explain.

Short Answer

Expert verified

$\frac{2}{3}$ is not a zero of functionlocalid="1646144029599" $f (x) = x^{7} + 6 x^{5} - x^{4} + x + 2$ becouse $f (\frac{2}{3}) 鈮� 0$

Step by step solution

01

Step 1. Given data

The given function is

$f (x) = x^{7} + 6 x^{5} - x^{4} + x + 2$

Zero of the function is $\frac{2}{3}$

02

Step 2. Verification

Substitute $\frac{2}{3}$ for x in the function

$f (x) = x^{7} + 6 x^{5} - x^{4} + x + 2 f (\frac{2}{3}) = {(\frac{2}{3})}^{7} + 6 {(\frac{2}{3})}^{5} - {(\frac{2}{3})}^{4} + (\frac{2}{3}) + 2 f (\frac{2}{3}) = 3.31 f (\frac{2}{3}) 鈮� 0$

$f (\frac{2}{3})$ is not equal to zero so $\frac{2}{3}$ is not a zero of the function

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