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In Problems 53–60, find all the complex roots. Leave your answers in polar form with the argument in degrees.

57. The complex fourth roots of-16i.

Short Answer

Expert verified

The complex fourth roots of-16iare2(cos67.5+isin67.5),2(cos157.5+isin157.5),2(cos247.5+isin247.5),2(cos337.5+isin337.5).

Step by step solution

01

Step 1. Rewrite -16i in the polar form.

The magnitude of -16iis

02+(-16)2=256=16

which gives

-16i=16(0-i)=16(cos270°-isin270°)

02

Step 2. Using the theorem of complex roots.

We get

zk=164[cos(2704+360k4)+isin(2704+360k4)];k=0,1,2,3=2[cos(67.5°+90°k)+isin(67.5°+90°k)]

03

Step 3. Substitute k=0,1,2,3 in zk=2[cos(67.5+90k)+isin(67.5+90k)].

We get

z0=2(cos37.5+isin67.5)z1=2[cos(67.5+90)+isin(67.5+90)]=2(cos157.5+isin157.5)z2=2[cos(67.5+180)+isin(67.5+180)]=2(cos247.5+isin247.5)z3=2[cos(67.5+270)+isin(67.5+270)]=2(cos337.5+isin337.5)

So we have found the complex fourth roots of -16i.

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