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Find the area of the parallelogram with verticesP1=1,1,1,P2=2,3,4,P3=6,5,2,andP4=7,7,5.

Short Answer

Expert verified

The area of the parallelogram is18.2square units.

Step by step solution

01

Step 1. Given Information

The given vertices areP1=1,1,1,P2=2,3,4,P3=6,5,2,andP4=7,7,5.

02

Step 2. Finding the area of the parallelogram

To find the area of the parallelogram we will use the formula Area=u×v.

Let's find the two adjacent sides of a parallelogram

u=P1P2→u=2-1i+3-1j+4-1ku=i+2j+3kv=P1P3→v=6-1i+5-1j+2-1kv=5i+4j+k

03

Step 3. Solve 

Let's find the cross product of the adjacent sides, the formula of the cross product isv×w=b1c2-b2c1i-a1c2-a2c1j+a1b2-a2b1k.

So,

u×v=i+2j+3k×5i+4j+ku×v=2·1-4·3i-1·1-5·3j+1·4-5·2ku×v=-10i+14j-6k

Now, use the formula of area of a parallelogram

Area=u×vArea=-10i+14j-6kArea=-102+142+-62Area=332Area≈18.2squareunits

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