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Find a vector v whose magnitude is 3 and whose component in the i direction is equal to the component in the j direction.

Short Answer

Expert verified

Vector v is 32i⇶Ä+32j⇶Ä

Step by step solution

01

Step. 1 Given 

|v| = 3 and,

angle of the vector from both i⇶Äandj⇶Ädirections is same suppose that angle be θ.

02

Step. 2 Vector representation

Now, As we know the general form of a vector is,

v⇶Ä=rcosθi⇶Ä+sinθj⇶Ä

where, r is the magnitude of the vector i.e., distance from the origin and θis the angle of that vector from x-axis or i⇶Ädirection.

Now, as magnitude in the question is given itself as 3. So,

role="math" localid="1646738176258" r=3.

So,

v⇶Ä=3cosθi⇶Ä+sinθj⇶Ä

03

Step. 3 Final solution

Now, we have left with only θ,

So, as it is given that it makes equal angles with and we know these directions are mutually perpendicular thatswhy

θ=45°orπ4,

Finally,

v⇶Ä=3cosÏ€4i⇶Ä+sinÏ€4j⇶Ä,v⇶Ä=3(i⇶Ä2+j⇶Ä2),v⇶Ä=32i⇶Ä+32j⇶Ä.

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