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find the area of the parallelogram with vertices P1 , P2 , P3 , and P4 .

P1=(2,1,1)P2=(2,3,1)P3=(-2,4,1)P4=(-2,6,1)

Short Answer

Expert verified

Area=5squnits

Step by step solution

01

Step 1. Area of parallelogram

We know that area of parallelogram is given as :

u→×v→

where ;

u and v being the vector of adjacent sides of parallelogram

02

Step 2. Solving for vectors u→ & v→

u→=P1P2u→=(2,3,1)-(2,1,1)u→=(0,2,0)v→=P1P4→v→=(-2,4,1)-(2,1,1)v→=(-4,3,0)

We can write these vectors as:

u→=0i^+2j^+0k^v→=-4i^+3j^+0k^

03

Step 3. Area is equals to

Area=|u→×v→|u→×v→=i^j^k^020-430u→×v→=i^(0)-j^(0)+k^(8)u→×v→=8k^⇒Area=|u→×v→|=8squnits

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