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In Problem, find the area of the parallelogram with one corner at P1 and adjacent sides

P1P2→andP1P3→

P1=1,2,0,P2=-2,3,4,P3=0,-2,3

Short Answer

Expert verified

The area of the parallelogram is :555

Step by step solution

01

Step1. Giving information 

three pointsP11,2,0,P2-2,3,4,P30,-2,3

We know that the vector is formed by two points like

A=x2-x1i+y2-y1j+z2-z1k

To given question

U=P1P2→U=-2-1i+3-2j+4-0kU=-3i+j+4klikethatv=-i-4j+3k

02

Step2. Calculation of cross product 

We know that to find the area of a parallelogram by two vectors. it's necessary to find an orthogonal vector, for that

u×v=ijk-314-1-43u×v=i14-43+j-34-13+k-31-1-4u×v=19i+5j+13k

03

Step3. Area of parallelogram

u×v=19i+5j+13ku×v=361+25+169u×v=555

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