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Why does the graph of a quadratic function open up if a>0and down if a<0?

Short Answer

Expert verified

When a>0then f(x)approaches positive infinity and hence it opens upwards

when a<0then f(x)approaches negative infinity and hence it opens downwards.

Step by step solution

01

Given information

Consider a quadratic equationf(x)=a(x-h)2+k

02

When a is positive

Now we evaluate,

f(∞)=a(∞-h)2+kf(∞)=a(∞)2+kf(∞)=∞Alsof(-∞)=a(-∞-h)2+kf(-∞)=a(-∞)2+kf(-∞)=∞

So when a>0then f(x)approaches positive infinity

03

When a is negative

Now we evaluate

f(∞)=-a(∞-h)2+kf(∞)=-a(∞)2+kf(∞)=-∞Alsof(-∞)=-a(-∞-h)2+kf(-∞)=-a(-∞)2+kf(-∞)=-∞

Whena<0thenf(x)approaches negative infinity

04

Conclusion

When a>0then f(x)approaches positive infinity and hence it opens upwards Similarly when a<0then f(x)approaches negative infinity and hence it opens downwards.

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