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Chapter 1: Q. 65 (page 41)

Find an equation for the line with the given properties. Express your answer using either the general form or the slope-intercept form of the equation of a line, whichever you prefer.

Perpendicular to the line y=12x+4; containing the point(1,-2).

Short Answer

Expert verified

The equation of the line isy=-2x.

Step by step solution

01

Step 1. Given information

The perpendicular line is y=12x+4.

The point is(1,-2)

02

Step 2. Finding the slope of line

Firstly, find the slope of perpendicular line

y=12x+4

Compare with slope-intercept formula

y=mx+b

So, slope is 12

Since slope of perpendicular line is always negative of inverse of the other line slope.

So, slope is

m=-112m=-2

03

Step 3. Finding the equation of line

The slope of line is

m=-2

The point is

(x1,y1)=(1,-2)

Apply point-slope formula

y-y1=m(x-x1)

Plug values

y+2=-2(x-1)y+2=-2x+2y+2-2=-2x+2-2y=-2x

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Most popular questions from this chapter

Graph the line containing the point P and having slope m.

P(2,4),m=-34

Can the equation of every line be written in slope鈥搃ntercept form? Why?

Determine the coordinates of the points shown. Tell in which quadrant each point lies. Assume the coordinates are integers.

Find the midpoint of the line segment joining the points P1 and P2 .

P1=(a,b);P2=(0,0)

Find the midpoint of the line segment joining the points P1 and P2 .

P1=(3,-4);P2=(5,4)
See all solutions

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