/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 33 Find (a) 聽the center (h, k) and... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Q. 33 (page 50)

Find (a) the center (h, k) and radius r of each circle; (b) graph each circle; (c) find the intercepts if any of the equation2x2+8x+2y2=0

Short Answer

Expert verified

a) center (h ,k), and the radius of the given equation are (-2,0) and 2

b) graph of the given equation is given below

Step by step solution

01

Part (a) step 1. Given information  

Given the equation of the circle is 2x2+8x+2y2=0

We have to Find (a) the center (h, k) and radius r of circle

02

 Part (a) Step 2. Rewriting the equation of a circle   

Here equation is in the form2x2+8x+2y2=0x2+4x+y2=0dividingby2getequationinstandardform(x2+4x)+y2=0

03

Part (a) step 3.  Find center and radius  

complete the square of each expression in parentheses, we get an

(x2+4x)+y2=0(x2+4x+4)+y2=4,sinceanynumberaddedontheleftsidemustaddtorightside(x+2)2+(y-0)2=22sothisstandardformofthecircleequaionwithcenterandradiushencecenteris(-2,0)andradiusis2.

Here x intercept and y intercept are both at 0.

04

Part (b)  step 1. Given information

Here given equation of a circle is2x2+8x+2y2=0

We need to sketch the graph

05

 Part (b) step 2. Graph of the equation of the circle  

the graph of the given equation with center(-2,0) and radius 2 is given below

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

True or False The point (-1,4)lies in quadrant IV of the Cartesian plane.

In Problem 17-36, solve each equation algebraically. Verify your solution using a graphing utility.

x-2=3

If -3and 5 are the coordinates of two points on the real number line, the distance between these points is _________.

Find the midpoint of the line segment joining the points P1 and P2 .

P1=(3,-4);P2=(5,4)

Find the midpoint of the line segment joining the points P1 and P2 .

P1=(a,b);P2=(0,0)
See all solutions

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Read Explanation

Probability and Statistics

Read Explanation

Calculus

Read Explanation

Geometry

Read Explanation

Mechanics Maths

Read Explanation

Discrete Mathematics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.