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Chapter 1: Q 25. (page 51)

Find an equation of the line having the given characteristics. Express your answer using either the general form or the

slope鈥搃ntercept form of the equation of a line, whichever you prefer. Graph the line.

Perpendicular to the line 3x-y=-4 containing the point-2,4.

Short Answer

Expert verified

Equation of line is 3x+y=-2. The graph for the equation is shown below.

Step by step solution

01

Step 1.  Given information .

Consider the given equation3x-y=-4and point-2,4.

02

Step 2. Formula used.

The slope intercept form of line y=mx+bis used to find the equation of line.

For two lines to be perpendicular m1m2=-1.

Rewrite the given equation in slope intercept form to find m1.

3x-y=-4y=3x+4m1=3,b=4

Substitute the value ofx,y to find m2.

y=m2x+b4=-2m2-2m2=-3

03

. Formula used.

The formula used to find equation of line is y-y1=mx-x1.

y-4=-3x+23x+y=-2

04

Step 4. Plot the graph .

The graph for the equation 3x-y=-4shown below .

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Most popular questions from this chapter

Find the midpoint of the line segment joining the points P1 and P2 .

P1=(a,a);P2=(0,0)

Graph the line containing the point P and having slope m.

P(-1,3),m=0

Graph the line containing the point P and having slope m.

P(2,4),m=-34

Determine the coordinates of the points shown. Tell in which quadrant each point lies. Assume the coordinates are integers.

If three distinct points P, Q, and R all lie on a line and if d(P,Q)=d(Q,R), then Q is called the _________ of the line segment from P to R.
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