/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 132 The figure shows the graph of tw... [FREE SOLUTION] | 91影视

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Chapter 1: Q. 132 (page 44)

The figure shows the graph of two perpendicular lines. Which of the following pairs of equations might have such a graph?

(a)y-2x=2y+2x=-1(b)y-2x=02y+x=0(c)2y-x=22y+x=-2(d)y-2x=2x+2y=-1(e)2x+y=-22y+x=-2

Short Answer

Expert verified

Equation(d)y-2x=2x+2y=-1might have such graph

Step by step solution

01

Given information

We are given a graph and equation

02

Explanation for correct option

Consider the option (d)y-2x=2x+2y=-1

Simplifying the equation and writing it in slope intercept form we get

y=2x+2y=-12x-12

On multiplying the slope we get -1

Hence the lines are perpendicular

03

Explanation for other options

Consider the equations

(a)y-2x=2y+2x=-1(b)y-2x=02y+x=0(c)2y-x=22y+x=-2(e)2x+y=-22y+x=-2

On simplifying the equation we get

(a)y=2x+2y=-2x-1(b)y=2xy=-12x(c)y=x2+1y=-x2-1(e)y=-2x-2y=-x2-1

On multiplying the slopes of equation of lines in options a) ,c) ,d) we do not get -1

And for option b) on multiplying the slopes we do get -1but the lines passes through the origin hence the given graph cannot be described by the lines

04

Conclusion

The equation(d)y-2x=2x+2y=-1might have such graph.

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