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Chapter 1: Q 12. (page 51)

Find the center and radius of the circle

x2+y2+4x-2y-4=0.Graph this circle.

Short Answer

Expert verified

Center and radius are -2,1and 3.

Graph of the equation shown below.

Step by step solution

01

Step 1. Given information.

Consider the given equation of the circle .

x2+y2+4x-2y-4=0

02

Step 2. Using the standard form of circle to rewrite the given equation in standard form.x-h2+y-k2=r2 where h,k are the center and r is radius.

x2+4x-2y-4+y2=0x--22+y-12=32

Therefore the circle properties .role="math" localid="1646038737236" h,k=-2,1andr=3

03

Ste[p 3. Plot the graph.

The graph of the given equation is shown below.

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Most popular questions from this chapter

True or false The point 1,2is on the line2x+y=4.

In Problem 17-36, solve each equation algebraically. Verify your solution using a graphing utility.

4y-5=182y

The equation 2x-y=Cdefines a family of lines, one line for each value of C. On one set of coordinate axes, graph the members of the family when C=-4,C=0and C=2. Can you draw a conclusion from the graph about each member of the family?

If two distinct lines have the same y

intercept, but different slopes, can they have the same x-intercept?

Find the midpoint of the line segment joining the points P1 and P2 .

P1=(3,-4);P2=(5,4)
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