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If f(x)=2x-Ax-3and f(4)=0, what is the value of A? Where is fnot defined?

Short Answer

Expert verified

The value ofA=8and atx=3function is not defined.

Step by step solution

01

Step 1. Given Information 

If f(x)=2x-Ax-3and f(4)=0

We have to find the value of Aand where is fnot defined.

02

Step 2. To find the value of A we firstly find the f(4) by putting x=4 in the given function.

f(4)=2×4-A4-3f(4)=8-A1f(4)=8-A

03

Step 3. Now the function is f(4)=8-A.We know f(4)=0 so we put the value of f(4) in the function.

0=8-A

Subtract 8 on both side

0-8=8-A-8-8=-A-A=-8

Multiply with -1on both side

-A×(-1)=-8×(-1)A=8

04

Step 4. To find, where is f is not defined, we put denominator of function equal to zero.

x-3=0

Add 3 on both side

x-3+3=0+3x=3

At x=3the function is not defined.

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