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91Ó°ÊÓ

Find the real solutions of the equation:

6x2-5x+1=0

Short Answer

Expert verified

The solution of the given equation is:

x=12x=13

Step by step solution

01

Step 1. Given information

The given equation is6x2-5x+1=0

02

Step 2. Factorise the equation

Using the factorisation method, we get:

6x2-5x+1=06x2-3x-2x+1=03x(2x-1)-(2x-1)=0[takingout3xand-1ascommon]2x-1(3x-1)=0

03

Step 3. Evaluating the value

Using zero product property, we get:

2x-1=02x=1x=12

or

3x-1=03x=1x=13

04

Step 4. Verify the solution

Substituting x=12in the given equation, we get:

6x2-5x+1=06122-512+1=06×14-5×12+1=032-52+1=0-22+1=0-1+1=00=0

This is true.

Substituting role="math" localid="1645888581245" x=13in the given equation, we get:

6x2-5x+1=06132-513+1=06×19-5×13+1=023-53+1=02-53+1=0-33+1=0-1+1=00=0

This is true.

Thus the solution of the given function is:

role="math" localid="1645888988809" x=12x=13

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