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Chapter 2: Q. 21 (page 124)

Determine(algebraically) whethere the given function is even, odd,or neither.

f(x)=x1+x2

Short Answer

Expert verified

The given functionf(x)=x1+x2is odd function

Step by step solution

01

Step 1.Given information

The given functionf(x)=x1+x2

02

Step 2.Determine the given function is even,odd or neither.

The function is even if f(-x)=f(x)and odd if f(-x)=f(-x).If none of these conditions are satisfied.

Find f(-x) by replacing -x for x in the given function.

f(-x)=-x1+(-x)2=-x1+x2=-x1+x2=-f(x)

Therefore,the given function is odd sincef(-x)=-f(x)

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