/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.89 (a) Graph f(x)=3x+1 and g(x)=2x... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) Graph f(x)=3x+1and g(x)=2x+2, on the same Cartesian plane.

(b) Find the points of intersection of the graphs of f and g by solving f(x)=g(x)Round answers to three decimal places. Label any intersection points on the graph drawn in part (a).

(c) Based on the graph, solve f(x)>g(x).

Short Answer

Expert verified

a) The graph can be given as

b) The point of intersection is (0.71.6.541)

c)f(x)>g(x)whenx>0.71

Step by step solution

01

Given information

We are given

f(x)=3x+1g(x)=2x+2

02

Part a) Step 2: Graph f(x)

We use a table to graph the function

x f(x)=3x+1
-2 13
-1 1
0 3
1 9
2 27

Similarly table for g(x)=2x+2can be given as

x g(x)=2x+2
-2 1
-1 2
0 4
1 8
2 16
03

Part a) Step 2: Graph the functions 

The graph can be given as

04

Part b) Step 1: Solve for f(x)=g(x)

We get,

f(x)=g(x)3x+1=2x+2ln(3x+1)=ln(2x+2)(x+1)ln3=(x+2)ln2x(ln3)+ln3=x(ln2)+2(ln2)x(ln3)-x(ln2)=2(ln2)-ln3x=2(ln2)-ln3(ln3)-(ln2)x=ln(43)ln32x=0.71

Now we find the corresponding function value

f(x)=3x+1f(0.71)=30.71+1f(0.71)=6.541

Hence the point of intersection is(0.71,6.541)

05

Part c)  Step1: Solve f(x)>g(x)

From part b) We know that the two graphs intersect at(0.71,6.541) and from the graph we can conclude thatf(x)>g(x)forx>0.71

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.