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91Ó°ÊÓ

Write each expression as a single logarithm.

lnx-1x+lnxx+1-lnx2-1

Short Answer

Expert verified

lnx-1x+lnxx+1-lnx2-1=ln1x+12

Step by step solution

01

Given data

The expression is :lnx-1x+lnxx+1-lnx2-1

02

Concept used

The properties of logarithms:

  • logaMN=logaM+logaN
  • logaMN=logaM-logaN
  • logaMr=rlogaM
  • ax=exlna
03

Evaluate

lnx-1x+lnxx+1-lnx2-1=lnx-1x·xx+1-lnx2-1; Using property of logarithms

role="math" localid="1646485237427" lnx-1x+lnxx+1-lnx2-1=lnx-1x+1-lnx2-1; Simplifying

role="math" localid="1646485345292" lnx-1x+lnxx+1-lnx2-1=lnx-1x+1x2-1; Using property of logarithms

role="math" localid="1646485414066" lnx-1x+lnxx+1-lnx2-1=lnx-1x+1x+1x-1; Using algebraic expression a2-b2=a-ba+b

lnx-1x+lnxx+1-lnx2-1=ln1x+12; Simplifying

role="math" localid="1646485500859" lnx-1x+lnxx+1-lnx2-1=ln1x+12

04

Conclusion

Thus,lnx-1x+lnxx+1-lnx2-1=ln1x+12

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