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Find an exponential function with horizontal asymptote y=2whose graph contains the points (0,3)and (1,5).

Short Answer

Expert verified

The exponential function isy=3x+2.

Step by step solution

01

Step 1. Use the given information.

Consider the given horizontal asymptote y=2.

The two points on the exponential function are (0,3)and (1,5).

If the horizontal asymptote is y=0, then the exponential function is y=ax.

If the horizontal asymptote is y=2, then the exponential function is y=ax+2.

02

Step 2. Finding exponential function.

On the point (1,5), the exponential function is

5=a1+25=a+2a=5-2a=3

So the exponential function isy=3x+2.

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