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If f(x)=3x2-7and g(x)=2x+a, find aso that the graph off∘g crosses the y-axis at 68.

Short Answer

Expert verified

The value of ais±5.

Step by step solution

01

Step 1. Given Information

Given that f(x)=3x2-7and g(x)=2x+a,value off∘g(x)atx=0is 68.

02

Step 2. Solution

We know that f∘g(x)=f(g(x)).

Here, f(x)=3x2-7,g(x)=2x+a

f∘g(x)=f(g(x))f∘g(x)=3(g(x))2-7 f∘g(x)=3{2x+a}2-7 f∘g(x)=3{4x2+4xa+a2}-7f∘g(x)=12x2+12xa+3a2-7

So, at x=0, f∘g(0)=68.

Now,

f∘g(x)=12x2+12xa+3a2-7,atx=0f∘g(0)=12(0)2+12(0)(a)+3a2-768=0+0+3a2-73a2=68+73a2=75a2=25a=±5.

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