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Suppose that f(x)=log2(x-2)+1.

(a) Graph f.

(b) What is f(6)? What point is on the graph of f ?

(c) Solve f(x)=4. What point is on the graph of f ?

(d) Based on the graph drawn in part (a), solve f(x)>0.

(e) Find f-1(x). Graphf-1 on the same Cartesian plane as f.

Short Answer

Expert verified

Part (a) Graph of fand f-1:

Part (b) f(6)=3;point on the graph: (6,3)

Part (c) f(10)=4;point on the graph: (10,4)

Part (d) 52,∞

Part (e)f-1(x)=2x-1+2

Step by step solution

01

Part (a) Step 1. Given information  

A function,f(x)=log2(x-2)+1

02

Part (a) Step 2. Graph of the function

Graph of the function is:

03

Part (b) Step 1. Finding f(6), and point on the the graph it represents

Given, f(x)=log2(x-2)+1

f(6)=log2(6-2)+1

f(6)=log24+1

f(6)=2+1

f(6)=3

The point on the graph is: (6,3)

04

Part (c) Step 1. Solving f(x)=4, and finding point on the graph it represents

Given, f(x)=4

log2(x-2)+1=4

log2(x-2)=4-1

x-2=23

x=8+2

x=10

The point on the graph is:(10,4)

05

Part (d) Step 1. Solving f(x)>0

Given, f(x)>0

⇒log2(x-2)+1>0

⇒log2(x-2)>-1

⇒x-2>2-1

⇒x>2+12

⇒x>52

06

Part (e) Step 1. finding and graphing f-1(x)

In the function, replace x by f-1(x)and f(x)by x and rearrange the variables to get inverse of the function.

x=log2(f-1(x)-2)+1

⇒x-1=log2(f-1(x)-2)

⇒2x-1=f-1(x)-2

⇒f-1(x)=2x-1+2

Graph of f-1:

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