/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 39 In Problems 29 – 44, for the g... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Problems 29 – 44, for the given functions f and g, find:

(a)f∘g

(b)g∘f

(c) f∘f

(d) g∘g

State the domain of each composite function.

f(x)=xg(x)=2x+3

Short Answer

Expert verified

a) f∘g=2x+3and its domain is:x≥-32

b)g∘f=2x+3 , and its domain:x≥0

c) f∘f=x4and its domain is:x≥0.

d) g∘g=4x+9and its domain is:-∞,∞

Step by step solution

01

Step 1. Given information:

The functions are:

f(x)=xg(x)=2x+3

The domain of f(x)={x|x≥0}

The domain ofg(x)is set of all real numbers.

02

Part (a)  Step 1. To find f∘g and its domain:  

f∘g=f(g(x))=2x+3

It is only defined when g(x)is defined and

2x+3≥0x≥-32

So its domain is:x≥-32

03

Part (a)  Step 1. To find g∘fand its domain:  

g∘f=g(f(x))=2x+3

This is only defined when f(x)is defined and x≥0.

So its domain is:x≥0

04

Part (c)  Step 1. To find f∘fand its domain:  

f∘f=f(x)=x=x4

This is only defined when f(x)is defined and x≥0.

So domain is:[0,∞)

05

Part (d)  Step 1. To find g∘gand its domain:  

g∘g∘=g(g(x))=g(2x+3)=2(2x+3)+3=4x+6+3=4x+9

This is defined for the set of all real values of x.

So domain is:(-∞,∞)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.