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Solve:log2(3x-2)+log2x=4

Short Answer

Expert verified

The solution of the given equation:x=-1,83

Step by step solution

01

Step 1. Given information

Given equation:

log2(3x-2)+log2x=4

02

Step 2. Solve the equation.

log2(3x-2)+log2x=4log2(3x-2)(x)=4

Take antilog on both sides.

x(3x-2)=243x2-2x=163x2-2x-16=03x2-8x+6x-16=0x(3x-8)+2(3x-8)=0(3x-8)(x+2)=03x-8=0x=83x+2=0x=-2

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