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On the 鈥淧rice is Right鈥 there is a game in which a bag is filled with 3 strike chips and 5 numbers. Let鈥檚 say that the numbers in the bag are 0, 1, 3, 6, and 9. What is the probability of selecting a strike chip or the number 1?

Short Answer

Expert verified

The probability is12

Step by step solution

01

Step 1. Given Information

The given data is that the numbers in the bag are 0, 1, 3, 6, and 9.

02

Step 2. Calculation  

The number of elements in the sample space are n(S)=3+5=8

The event E1consists of all the strike chips. So, probability of selecting a strike chip is P(E1)=38

The event E2consists of only the number 1. So, probability of selecting number 1 is role="math" localid="1647005899037" P(E2)=18

Thus, the probability of selecting a strike chip or number 1 is as follows,

P(E)=P(E1)+P(E2)=38+18=48=12

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