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91Ó°ÊÓ

Geometry Find the value of the angle θin degrees rounded to the nearest tenth of a degree.

Short Answer

Expert verified

The answer is θ=38.9°.

Step by step solution

01

Step 1. Given information

We have two circles small circle have radius r1 = 2 and bigger circle have radius r2 = 4.

These two circle has two common tangents meeting at some point at an angle θ.

Given:

PS=2QC=4∠POS=∠QOC=θ2.(SinceitsymmetricaboutthelinedrawnfromO).SC=2+4=6,And∠OPS=∠OQC=90°.(Sincethetangentisperpendiculartothecircle.)

02

Step 2. Triangles and its properties

In∆POS,sinθ2=PSOS.In∆QOC,sinθ2=QCOC=QCOS+SC.

03

Step 3. Solving the equations from step 2

sinθ2=PSOS=2OS,Now,sinθ2=QCOS+SC,2OS=4OS+6,SolvingforOSweget,2OS+12=4OS,2OS=12,OS=6,Nowfromaboveequation,sinθ2=2OS=26=13,θ2=sin-113,θ=2sin-113,θ=38.9424....°θ≅38.9°.

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