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91Ó°ÊÓ

In the given problem solve the triangle using either the law of sines or law of cosines-

a=10,b=10,c=15

Short Answer

Expert verified

Required values of the triangle are

A=138.59°,B=41.29°,C=81.89°

Step by step solution

01

Step 1. Given information

In the given triangle,

a=10,b=10,c=15

We know,

Law of cosines,

a2=b2+c2-2bccosA --------1

Law of sines,

sinAa=sinBb=sinCc ---------2

02

Step 2. Calculation

For A, using equation 1

role="math" localid="1646736804050" a2=b2+c2-2bccosA⇒102=102-152-2×10×15cosA⇒300cosA=-225⇒cosA=-225300⇒A=cos-1-0.75⇒A=138.59°

For Band C, using 2

sinAa=sinBb⇒sin138.59°10=sinB10⇒sinB=0.66⇒B=sin-10.66=41.29°

Also,

sinBb=sinCc⇒sin(41.29°)10=sinC15⇒sinC=0.6610×15⇒sinC=0.99⇒C=sin-10.99=81.89

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