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91Ó°ÊÓ

In the given problem solve the triangle using either the law of sines or law of cosines-

b=5,c=12,A=60°

Short Answer

Expert verified

Required values of the triangle are

a=10.44,B=13.8°,C=34.75°

Step by step solution

01

Step 1. Given information

In the given triangle,

b=5,c=12,A=60°

We know Law of cosines,

a2=b2+c2-2bccosA -------1

Also, Law of sines,

sinAa=sinBb=sinCc -------2

02

Step 2. Calculation

For a, using equation 1

a2=b2+c2-2bccosA⇒a2=52+122-2×5×12.cos60°⇒a2=25+144-120×0.5⇒a2=109⇒a=10.44

For B, using equation 2

sinAa=sinBb⇒sin60°10.44=sinB5⇒0.510.44=sinB5⇒sinB=0.239⇒B=sin-10.239⇒B=13.8°

For C, using equation 2

sinAa=sinCc⇒sin60°10.44=sinC12⇒sinC=0.5×1210.44⇒sinC=0.57⇒C=sin-10.57⇒C=34.75°

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