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Two sides and an angle are given. Determine whether the given information results in one triangle, two triangles, or no triangle at all. Solve each triangle that resultsb=4,c=5,B=40°

Short Answer

Expert verified

With the given measurements two triangles are possible.

For△A1BC1,a1=6.2,b=4,c=5,A1=86.55°,B=40°,C1=53.45°For△A2BC2,a2=1.4,b=4,c=5,A2=13.45°,B=40°,C2=126.55°

Step by step solution

01

Step 1. Given information

b=4,c=5,B=40°

For a triangle with sides a, b, c and opposite angles A, B, C, respectively, Law of sines is given as:

sinAa=sinBb=sinCc

02

Step 2. Calculation

ByLawofSines,ForC,⇒sinBb=sinCc⇒sinC=sinB×cb=sin40°×54=0.6427×1.25=0.803375C1≈53.45°orC2≈180°-53.45°=126.55°Since,C1+B<180°,△A1BC1ispossibleandC2+B<180°,△A2BC2ispossible.In△A1BC1:ForA1,⇒A1=180°-B-C1=180°-40°-53.45°=180°-93.45°=86.55°Fora1,⇒sinBb=sinA1a1⇒a1=sinA1×bsinB=sin86.55°×4sin40°=0.9981×40.6427=3.99240.6427=6.2In△A2BC2:ForA2,⇒A2=180°-40°-126.55°=180°-166.55°=13.45°Fora2,⇒sinBb=sinA2a2⇒a2=sinA2×bsinB=sin13.45°×4sin(40°)=0.2325×40.6427=0.930.6427=1.447≈1.4

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