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Two sides and an angle are given. Determine whether the given information results in one triangle, two triangles, or no triangle at all. Solve each triangle that results b=4,c=6,B=20°

Short Answer

Expert verified

With the given measurements two triangles are possible.

For△A1BC1,a1=4.5,b=4,c=6,A1=129.14°,B=20°,C1=30.86°For△A2BC2,a2=3.3,b=4,c=6,A2=10.86°,B=20°,C2=149.14°

Step by step solution

01

Step 1. Given information

b=4,c=6,B=20°

For a triangle with sides a, b, c and opposite angles A, B, C, respectively, Law of sines is given as:

sinAa=sinBb=sinCc

02

Step 2. Calculation

ByLawofSines,ForC,⇒sinBb=sinCc⇒sinC=sinB×cb=sin20°×64=0.342×1.5=0.513C1≈30.86°orC2≈180°-30.86°=149.14°Since,C1+B<180°,△A1BC1ispossibleandC2+B<180°,△A2BC2ispossible.In△A1BC1:ForA1,⇒A1=180°-B-C1=180°-20°-30.86°=180°-50.86°=129.14°Fora1,⇒sinBb=sinA1a1⇒a1=sinA1×bsinB=sin129.14°×4sin20°=0.7756×20.342=1.55120.342=4.535≈4.5In△A2BC2:ForA2,⇒A2=180°-20°-149.14°=180°-169.14°=10.86°Fora2,⇒sinBb=sinA2a2⇒a2=sinA2×bsinB=sin10.86°×4sin(20°)=0.1884×40.342=1.13540.342=3.3198≈3.3

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