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Two sides and an angle are given. Determine whether the given information results in one triangle, two triangles, or no triangle at all. Solve each triangle that results b=2,c=3,B=40°.

Short Answer

Expert verified

With the given measurements two triangles are possible.

For△A1BC1,a1=2.8,b=2,c=3,A1=65.41°,B=40°,C1=74.59°For△A2BC2,a2=1.8,b=2,c=3,A2=34.59°,B=40°,C2=105.41°

Step by step solution

01

Step 1. Given information 

b=2,c=3,B=40°

For a triangle with sides a, b, c and opposite angles A, B, C, respectively, Law of sines is given as:

localid="1646983063347" sinAa=sinBb=sinCc

02

Step 2. Calculation

ByLawofSines,ForC,⇒sinBb=sinCc⇒sinC=sinB×cb=sin40°×32=0.6427×1.5=0.96405C1≈74.59°orC2≈180°-74.59°=105.41°Since,C1+B<180°,△A1BC1ispossibleandC2+B<180°,△A2BC2ispossible.In△A1BC1:ForA1,⇒A1=180°-B-C1=180°-40°-74.59°=180°-114.59°=65.41°Fora1,⇒sinBb=sinA1a1⇒a1=sinA1×bsinB=sin65.41°×2sin40°=0.9093×20.6427=1.81860.6427=2.8296≈2.8In△A2BC2:ForA2,⇒A2=180°-40°-105.41°=180°-145.41°=34.59°Fora2,⇒sinBb=sinA2a2⇒a2=sinA2×bsinB=sin34.59°×2sin(40°)=0.5677×20.6427=1.13540.6427=1.7666≈1.8

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