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Chapter 7: Q.6 (page 473)

True or False: sin-胃+sin胃=0for any value of theta

Short Answer

Expert verified

Given statement is true statement

Step by step solution

01

Given information

We are given an trigonometric identitysin-胃+sin胃

02

Explanation for true statement

We know that sine is an odd function

Hence sin-胃=-sin胃

Hence we get,

sin-胃+sin胃-sin胃+sin胃=0

For any value of theta

03

Explanation for false statement

Suppose

sin-胃+sin胃鈮�0

But sine is an odd function

hence sin-胃=-sin胃

Which is a contradiction to our assumption

Hence our assumption is wrong

And therefore

sin-胃+sin胃-sin胃+sin胃=0

04

Conclusion

Given statement is true statement

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