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Chapter 7: Q. 91 (page 487)

solve each equation on the interval 0鈮�胃<2蟺

sin胃-3cos胃=1

Short Answer

Expert verified

胃=(n蟺+蟺3)+(-1)(n)蟺6

Step by step solution

01

Step 1.Given information is

a trignometric equationsin胃-3cos胃=1

02

Step 2.multiplying both the side by 12, we get12sinθ-32cosθ=12cosπ3sinθ-sinπ3cosθ=sinπ6sinθ-π3=sinπ6

we know that

cos蟺3=12,sin蟺3=32

03

Step 3.the general solution we get is

胃=n蟺+(-1)n蟺6+蟺3

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