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Precalculus Enhanced with Graphing Utilities

Sullivan

$Math Studyset 91影视 Explanations$ Math

6th Edition 路 1200 pages

ISBN: 9780321795465

Chapter 7: Q. 86 (page 458)

Consult three books on calculus and write down the
definition in each of $y = s e c^{- 1} x$ and $y = \cos e c^{- 1} x$ . Compare
these with the definitions given in this book.

Short Answer

Expert verified

Both are continous function.

Step by step solution

01

Step 1. Given Information

$y = s e c^{- 1} x a n d y = \cos e c^{- 1} x$

02

Step 2. Explanation

$y = s e c^{- 1} x A c o n t i n o u s f u n c t i o n w h e r e |x| 鈮� 1 a n d 0 鈮� y < \frac{蟺}{2}, \frac{蟺}{2} 鈮� y < \frac{3 蟺}{2} y = \cos e c^{- 1} x A c o n t i n o u s f u n c t i o n w h e r e |x| 鈮� 1 a n d - 蟺 < y 鈮� - \frac{蟺}{2}, 0 < y 鈮� \frac{蟺}{2}$

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Most popular questions from this chapter

$\cos (2 胃) = \cos^{2} 胃 -$ $=$ $- 1 = 1 -$ .

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