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Use a graphing utility to solve the equation on the interval 0≤x≤2π. Approximate any solutions rounded to two decimal places.

2cos-1x+Ï€=4cos-1x

Short Answer

Expert verified

The exact solution of the equation is 0.

Step by step solution

01

Step 1. Given information.

Consider the given question,

2cos-1x+Ï€=4cos-1x

Subtract2cos-1xfrom both sides,

2cos-1x+π-2cos-1x=4cos-1x-2cos-1xπ=4cos-1x-2cos-1xπ=2cos-1x

Divide both sides by 2,

Ï€2=2cos-1x2Ï€2=cos-1x

02

Step 2. Rewrite the equation.

As y=sin-1xmeans x=siny, where,

-π2≤θ≤π2

On rewriting the equation, we get,

localid="1646497927832" x=cosπ2x=0

Therefore, the solution set is{0}

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