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Chapter 7: Q. 71 (page 504)

In Problems 64-75, solve each equation on the interval0鈮�胃<2蟺

Short Answer

Expert verified

The solution set is胃鈭�0,蟺6,5蟺6

Step by step solution

01

Given information

Given expressionsin(2胃)-cos胃-2sin胃+1=0

02

Checking the value lie in the specific interval

Calculating, we get

sin(2胃)-cos胃-2sin胃+1=02sin胃cos胃-cos胃-2sin胃+1=02sin胃(cos胃-1)-(cos胃-1)=0(cos胃-1)(2sin胃-1)=0cos胃-1=0cos胃=12sin胃-1=02sin胃=1sin胃=12胃鈭�0,蟺6,5蟺6

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Most popular questions from this chapter

Show thatsin3胃+sin3胃+120掳+sin3胃+240掳=-34sin3胃

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True or False:

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