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In Problems 69-78, solve each equation on the interval 0≤θ<2π.

cos2θ=2-2sin2θ.

Short Answer

Expert verified

The equation cos2θ=2-2sin2θhas no solution (i.e), θ∈ϕ.

Step by step solution

01

Step 1 Given equation is,

cos2θ=2-2sin2θ.

we know that, cos2θ=1-2sin2θ

Substitute the known values in the given equation.

1-2sin2θ=2-2sin2θ1≠2

02

Step 2 The above equation indicates that the given equation has no solution.

So, the solution set is, θ∈{ϕ}.

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